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python入门作业编程题

import randomscore_num = {}for _ in range(1000): score = random.randint(1, 100) score_num[score] = score_num.get(score, 0) + 1num_scores = {}print('作业5:统计分数出现次数')for score, num in sorted(score_num.items(), key=lambda sn:

def score(numbers): return sum(sorted(numbers)[1:-1]) / float(len(numbers) - 2)

由已知:dt["成绩"]["英语"][0]为张唐的英语成绩dt["成绩"]["政治"][0]为张唐的政治成绩dt["成绩"]["Python程序设计"][0]为张唐的Python程序设计成绩dt["成绩"]["英语"][1]为李丽的英语成绩dt["成绩"]["政治"][1]为李丽的政治成绩dt["成绩"]["Python程序设计"][1]为李丽的Python程序设计成绩计算即可得出平均成绩p

def func(day): sumd=day//7 lev=1 while sumd>=0: sumd=sumd-1 for i in range(4): lev=lev+lev*0.01 n=day%7 if n<=3: return lev if n>3: sumd=n-3 while sumd>0: sumd=sumd-1 lev=lev+0.01 return leva=func(365)print(a)虽然方法笨了点,这样应该计算连续365没问题,最终好像是8.几

选B.Consider this statement in Python: //假设下面为袭Python语句print ("One", "Two", "Three")//"One" is considered a/n://"One" 被当做是A. The name of a function //函数2113名B. Argument //参数5261C. A variable //变量4102D. A numeric literal//数字字面量print是个函数,调用函数时,函数括号1653中为实际参数.故选B,参数.

x = "a string variable"y = isinstance(x, float) or isinstance(x, str) or isinstance(x, int) or isinstance(x, complex)print(y)

简单排序的话,直接使用 list.sort() 就可以了,直接在原列表上进行排序.非要写成函数的形式的话,代码如下 def abc(nums_l): nums_l.sort() return nums_l l = [1,2,5,3,4]# 其实,使用 l.sort() 之后,就对l进行了排序,然后输出l就可以了 print l

for k in range(1,51): total += (k*k)

n=0 b=n+1 print("开始计算1+2+3++100") ok=False while b==False int(input(b)) if b=100 print(ok) ok=True 绞尽脑汁后 【只觉得没程序天赋】 n=0 b=0+1 s=n+b while s == 100: print("ok")

def get_previous_words_dict(text): text_list = text.split() dic = dict() for k in range(0, len(text_list)): dic[text_list[k]] = [] for i in range(0, len(text_list)): if i == 0: dic[text_list[i]] = [''] else: if text_list[i - 1] not in dic[text_list[i]]: dic[text_list[i]] += [text_list[i - 1]]

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